/Python/Python get first n elements of dict

Python get first n elements of dict

Access first element of dictionary python

res = next(iter(test_dict))

Take first n row of dictionary python

a_dictionary = {"name" : "John", "age" : 35, "height" : 65}

dict_items = a_dictionary.items()

first_two = list(dict_items)[:2]
print(first_two)

OUTPUT
[('name', 'John'), ('age', 35)]

first_three = list(dict_items)[:3]
print(first_three)

OUTPUT
[('name', 'John'), ('age', 35), ('height', 65)]

Python get first n elements of dict

"""
NOTE: dictionaries do NOT remember the order in which 
key : value pairs have been stored
"""
d = {"a" : 5, "b" : 1, "c" : 8, "d" : 4, "e" : 3, "f" : 10, "g": 2}
# getting the first n key : value pairs
n = 3
first_n = dict(zip(list(d.keys())[:n], list(d.values())[:n]))
first_n
>>> {'a': 5, 'b': 1, 'c': 8}

Similar codes

0 vote126 views1 answer
Login views django template passing
Python
0 vote141 views1 answer
Is python3 enough for react native
Python
0 vote108 views1 answer
Python update header row
Python
-1 vote109 views1 answer
Python pandas dataframe conditional subset
Python
0 vote143 views1 answer
Form valid django created by
Python Django
0 vote115 views1 answer
How to capture multiple screens with ImageGrab
Python
28 votes124 views3 answers
Round down a number python
Python
1 vote141 views3 answers
Check cuda version pytorch
Python
0 vote132 views1 answer
Python breadth first search
Python
0 vote74 views3 answers
Django messages
Python