Python perfect square

Setting a condition for perfect square in python

import math

# Taking the input from user
number = int(input("Enter the Number"))

root = math.sqrt(number)
if int(root + 0.5) ** 2 == number:
    print(number, "is a perfect square")
else:
    print(number, "is not a perfect square")

Source: djangocentral.com

Python perfect square

import math

def is_square(n):
    return n > -1 and math.sqrt(n) % 1 == 0


# Taking the input from user
number = int(input("Enter the Number: "))
if is_square(number):
    print(f'Your number: {number} is perfect square.')
else:
    print(f'Your number: {number} is not perfect square.')

Python num perfect squares

print(int(int(n)**.5))

Similar codes

0 vote131 views1 answer
Python cv2 read image grayscale
Python
0 vote129 views1 answer
Dependency on app with no migrations:
Python
1 vote175 views2 answers
Django make new application folder
Python Django
0 vote137 views1 answer
``` discord newline doesn't work python
Python
1 vote151 views5 answers
Transpose matrix python
Python
4 votes242 views1 answer
Create or update django models
Python Django
16 votes137 views1 answer
Python reload module without restarting
Python
0 vote142 views1 answer
How to iterate row wise using 2d integer array in python
Python
0 vote133 views1 answer
Pyqt5 qpushbutton disable
Python
0 vote137 views2 answers
Python closing socket good way
Python