Python perfect square

Setting a condition for perfect square in python

import math

# Taking the input from user
number = int(input("Enter the Number"))

root = math.sqrt(number)
if int(root + 0.5) ** 2 == number:
    print(number, "is a perfect square")
else:
    print(number, "is not a perfect square")

Source: djangocentral.com

Python perfect square

import math

def is_square(n):
    return n > -1 and math.sqrt(n) % 1 == 0


# Taking the input from user
number = int(input("Enter the Number: "))
if is_square(number):
    print(f'Your number: {number} is perfect square.')
else:
    print(f'Your number: {number} is not perfect square.')

Python num perfect squares

print(int(int(n)**.5))

Similar codes

1 vote196 views2 answers
Python str prefix
Python
0 vote246 views1 answer
Python - How To Check Operating System
Python
0 vote215 views1 answer
Connectionrefusederror at /accounts/signup/ django allauth
Python
3 votes223 views2 answers
Python dict order a dict by key
Python
0 vote197 views1 answer
Discord.File(fp=image_binary,filename=name) discord py
Python
0 vote275 views2 answers
Python code checker
Python
1 vote189 views1 answer
Postgresql connect with local machine in django
Python Django
0 vote217 views1 answer
Create pandas df without column name toy dataset
Python
2 votes305 views1 answer
How to return total elements in database django
Python Django
30 votes411 views3 answers
Django createsuperuser
Python Django