Python perfect square

Setting a condition for perfect square in python

import math

# Taking the input from user
number = int(input("Enter the Number"))

root = math.sqrt(number)
if int(root + 0.5) ** 2 == number:
    print(number, "is a perfect square")
else:
    print(number, "is not a perfect square")

Source: djangocentral.com

Python perfect square

import math

def is_square(n):
    return n > -1 and math.sqrt(n) % 1 == 0


# Taking the input from user
number = int(input("Enter the Number: "))
if is_square(number):
    print(f'Your number: {number} is perfect square.')
else:
    print(f'Your number: {number} is not perfect square.')

Python num perfect squares

print(int(int(n)**.5))

Similar codes

0 vote97 views2 answers
Numpy round to nearest 5
Python
0 vote111 views1 answer
Open anarchy ip
Python
9 votes116 views1 answer
Delete model object django
Python Django
0 vote104 views1 answer
Random ordered slice of an array
Python
3 votes96 views1 answer
Make tkinter label and input
Python
0 vote94 views1 answer
How to use ggplot matplotlib
Python
1 vote97 views1 answer
Acess nvidia from docker compose
Python
0 vote100 views1 answer
Genshin impact checker python
Python
0 vote100 views2 answers
Django create view filter options
Python
1 vote97 views5 answers
Transpose a matrix in python
Python