Python dict order a dict by key

Sort dictionary python

l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = dict(sorted(l.items(),key=lambda x:x[1],reverse=True))
print(d1) #output : {2: 60, 3: 50, 1: 40, 4: 30, 5: 20}
d2 = dict(sorted(l.items(),key=lambda x:x[1],reverse=False))
print(d2) #output : {5: 20, 4: 30, 1: 40, 3: 50, 2: 60}

Python dict order a dict by key

d1 = dict(sorted(d.items(), key = lambda x:x[0]))

Source: stackoverflow.com

Similar codes

0 vote102 views1 answer
Redirect stdout to variable python
Python
-1 vote134 views2 answers
Django forms error customize
Python Django
0 vote102 views1 answer
Lamda in f string
Python
1 vote124 views1 answer
Ls.ProgrammingError: permission denied for table django_migrations
Python Django
0 vote95 views1 answer
Execute command dynamo civid
Python
1 vote105 views1 answer
Pyo example
Python
18 votes108 views2 answers
Open an exe file using python
Python
0 vote97 views1 answer
Check check writability of the file
Python
0 vote92 views1 answer
Kivy video recorder
Python
0 vote114 views1 answer
Read ms word with python
Python