Varargs java

public static void printNumberOfArguments(int... numbers) {
    System.out.println(numbers.length);
}
printNumberOfArguments(1);
printNumberOfArguments(1, 2);
printNumberOfArguments(1, 2, 3);
printNumberOfArguments(new int[] { }); // no arguments here
printNumberOfArguments(new int[] { 1, 2 });

Varargs java

If a method has more than one parameter, the vararg parameter must be the last one in the declaration of the method

Varargs java

varargs:
It's possible to pass an arbitrary number of the same type arguments to 
a method using the special syntax named varargs (variable-length arguments).
 (Varargs can be used when we are unsure about the number of 
 arguments to be passed in a method)
Use varargs for any method (or constructor) that needs an array of
T (whatever type T may be) as input
One good example is String.format.
The format string can accept any number of parameters.

Similar codes

1 vote105 views1 answer
Java to kotlin converter
Java
-1 vote163 views2 answers
How to use spring in java
Java
-2 votes151 views1 answer
Java array repeating
Java
0 vote106 views1 answer
Parcourir string java
Java
0 vote146 views1 answer
Hide elements android
Java
-1 vote176 views2 answers
How to disable the cors in spring boot
Java
0 vote166 views1 answer
Unprocessed continuation reference(s) remaining name
Java
0 vote166 views1 answer
Java count files in folder
Java
3 votes117 views1 answer
How to check a integer in java
Java
0 vote193 views1 answer
They say that they have to create an instance to their application. What does it mean?
Java