Hibernate/JPA criteria query

import javax.persistence.criteria.CriteriaBuilder;
import javax.persistence.criteria.CriteriaQuery;
import javax.persistence.criteria.Root;
import org.hibernate.Session;
import org.hibernate.SessionFactory;

try (Session session = sessionFactory.openSession()) {
      CriteriaBuilder criteriaBuilder = session.getCriteriaBuilder();
      CriteriaQuery<Integer> query = criteriaBuilder.createQuery(Integer.class);
      Root<RevisionInfoData> root = query.from(RevisionInfoData.class);
      query
          .select(root.get("revisionNumber"))
          .orderBy(criteriaBuilder.desc(root.get("revisionNumber")));
      return ImmutableSet.copyOf(session.createQuery(query).getResultList());
}

Similar codes

-2 votes136 views1 answer
How to saperate string to array
Java
24 votes132 views6 answers
Java public static void main
Java
0 vote164 views1 answer
Linked list implementation in Java source code
Java
0 vote130 views2 answers
Spring tag library in jsp header
Java
0 vote129 views2 answers
Static import java
Java
0 vote146 views1 answer
Java.lang.NullPointerException: Attempt to invoke virtual method 'void android.widget.TextView.setText(java.lang.CharSequence)' on a null object reference
Java
-4 votes165 views2 answers
Spring security logging
Java Spring
50 votes148 views2 answers
Find number of weeks between two dates in java
Java
1 vote131 views1 answer
Java transfer file over socket
Java
1 vote128 views1 answer
Arraylist index java
Java