Alphabet position in python

Position in alphabet python

from string import ascii_lowercase
LETTERS = {letter: str(index) for index, letter in enumerate(ascii_lowercase, start=1)} 

def alphabet_position(text):
    text = text.lower()
    numbers = [LETTERS[character] for character in text if character in LETTERS]
    return ' '.join(numbers)

Source: grepper.com

Similar codes

0 vote134 views2 answers
Python function overloading
Python
32 votes138 views6 answers
Array in python
Python
-2 votes145 views1 answer
Stats.norm.cdf(2,loc=mean, scale=std_dev)
Python
-2 votes154 views9 answers
Django
Python
77 votes137 views6 answers
Reverse a string python
Python
0 vote133 views1 answer
Eastvale roblox python
Python
1 vote141 views2 answers
Code help
Python
0 vote130 views1 answer
Check if path is a folder python
Python
11 votes145 views4 answers
Invert a dictionary python
Python
2 votes132 views2 answers
Python longest list in list
Python