Alphabet position in python

Position in alphabet python

from string import ascii_lowercase
LETTERS = {letter: str(index) for index, letter in enumerate(ascii_lowercase, start=1)} 

def alphabet_position(text):
    text = text.lower()
    numbers = [LETTERS[character] for character in text if character in LETTERS]
    return ' '.join(numbers)

Source: grepper.com

Similar codes

0 vote186 views1 answer
Frequency unique pandas
Python
0 vote193 views1 answer
Python string equals
Python
1 vote205 views1 answer
Parcourir une liste par la fin python
Python
3 votes190 views2 answers
Python use variable in another file
Python
6 votes240 views2 answers
Flask get ip address of request
Python Flask
1 vote189 views2 answers
How to download python freegames
Python
3 votes173 views5 answers
Kwargs in python
Python
0 vote187 views1 answer
Dynamically created queryset for PrimaryKeyRelatedField in drf
Python
0 vote164 views6 answers
Assign dictionary a value from a list python
Python
12 votes189 views4 answers
Python list intersection
Python