Python pattern

Python re compile

import re
#	Compile a regular expression pattern into a regular expression object, which can be used for matching using its match(), search() and other methods, described below.

prog = re.compile(pattern)
result = prog.match(string)

#	is equivalent to

result = re.match(pattern, string)

Source: docs.python.org

Pattern in python

rows = 6                        #Pattern(1,121,12321,1234321,123454321)
for i in range(1, rows + 1):
    for j in range(1, i - 1):
        print(j, end=" ")
    for j in range(i - 1, 0, -1):
        print(j, end=" ")
    print()

Pattern program in python

k=int(input('value of a: '))
for a in range(1,k):
    for b in range(1,k):
        if a==b:
            print('A',end=" ")
        else:
            print('B',end=" ")
        
    print()
________________________________________________________________________________

Pattern in python

j="ramkumar"
for i in range(len(j)):
    for g in range(0,i+1):
        print(j[g],end=' ')
    print('')
# end='' meaning (print the next answer , near the previous answer in same line)
#answer 1 2 3 4 5 6 like this in same row or same line(in horizontal)



name="ramkumar"
for i in range(len(name)) :
    print(name[0:i+1])

* pattern by python

def pattern(n):    
  for i in range(0,n):       
    for j in range(0, i+1): 
      print("* " , end="")         
      print("\r") pattern(5

Python pattern

        python
        
            
        
     import re
v = "aeiou"
c = "qwrtypsdfghjklzxcvbnm"
print(*re.findall("(?=[%s]([%s]{2,})[%s])"%(c,v,c),input(), re.I) or [-1], sep="\n")

-1

Source: thepoorcoder.com

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