/Java/Java scanner string nextline after nextint

Java scanner string nextline after nextint

//The problem is with the input.nextInt() method - it only reads the int value. So when you continue reading with input.nextLine() you receive the "\n" Enter key. So to skip this you have to add the input.nextLine(). Hope this should be clear now.

//Try it like that:

System.out.print("Insert a number: ");
int number = input.nextInt();
input.nextLine(); // This line you have to add (It consumes the \n character)
System.out.print("Text1: ");
String text1 = input.nextLine();
System.out.print("Text2: ");
String text2 = input.nextLine();

Source: stackoverflow.com

Sc.nextline skips

int option = input.nextInt();
input.nextLine();  // Consume newline left-over
String str1 = input.nextLine();

Source: stackoverflow.com

Similar codes

0 vote139 views1 answer
How to et curent directory in java
Java
0 vote146 views1 answer
Test excel file java multipart
Java
4 votes146 views4 answers
Convert list of integer to array in java
Java
1 vote121 views1 answer
How to addin java
Java
1 vote129 views1 answer
Java question mark operator
Java
0 vote140 views1 answer
What does this means error: cannot find symbol StorageRef.child(mUser()).putFile(imageUri).addOnCompleteListener(new OnCompleteListener<UploadTask.TaskSnapshot>()
Java
4 votes148 views3 answers
Reverse string using recursion java with explanation
Java
0 vote134 views1 answer
H2-gramer-conf
Java
0 vote174 views1 answer
Spring org.springframework.stereotype not visible
Java
1 vote124 views1 answer
Binary Search Descending Order Sorted Array
Java