Sorting a dictionary in python

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Sorting a dictionary in python

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Source: stackoverflow.com

Sort dictionary python

l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = dict(sorted(l.items(),key=lambda x:x[1],reverse=True))
print(d1) #output : {2: 60, 3: 50, 1: 40, 4: 30, 5: 20}
d2 = dict(sorted(l.items(),key=lambda x:x[1],reverse=False))
print(d2) #output : {5: 20, 4: 30, 1: 40, 3: 50, 2: 60}

Sort the dictionary in python

d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)

Python sort the values in a dictionary

from operator import itemgetter
new_dict = sorted(data.items(), key=itemgetter(1))

Sort dictionary

#for dictionary d
sorted(d.items(), key=lambda x: x[1]) #for inceasing order
sorted(d.items(), key=lambda x: x[1], reverse=True) # for decreasing order
#it will return list of key value pair tuples

Similar codes

2 votes171 views2 answers
How to split a list to 1000 items python
Python
0 vote275 views1 answer
Python tableau a 2 dimensions
Python
0 vote210 views1 answer
How to find mean of one column based on another column in python
Python
0 vote186 views1 answer
How to read panda column
Python
9 votes162 views2 answers
TypeError: 'method' object is not subscriptable
Python
0 vote192 views1 answer
Read text file line by line using the readline() function
Python
0 vote147 views1 answer
/usr/local/lib/python3.7/dist-packages/pytube/captions.py in xml_caption_to_srt(self, xml_captions)
Python
15 votes198 views3 answers
Python current year
Python
5 votes185 views2 answers
Python 3 replace all whitespace characters
Python
0 vote215 views1 answer
Create django model field based on another field
Python Django