/SQL/Comparing with today and yesterday record in sql query

Comparing with today and yesterday record in sql query

declare @bgn_dt date = '2017-12-15' --set by OP
    , @end_dt date = '2017-12-22' --set by OP
    , @lag_dt date;

set @lag_dt = (select max(MyDate) from #myTable where MyDate < @bgn_dt) --get the "yesterday" that the @bgn_dt will need

select a.MyDate
, a.SalesTotal
, format(((1.0 * a.SalesTotal) / a.SalesTotalPrevDay) - 1, '0%') as SalesTotalChange
from (
    select t.MyDate
    , t.SalesTotal
    , lag(t.SalesTotal, 1, NULL) over (/*partition by (if needed)*/ order by t.MyDate asc) as SalesTotalPrevDay
    from #myTable as t
    where 1=1
    and t.MyDate between @lag_dt and @end_dt
    ) as a
where 1=1
and a.MyDate >= @bgn_dt

Source: stackoverflow.com

Similar codes

0 vote143 views1 answer
Sql cnvert bit to nvarchar
SQL
12 votes189 views2 answers
Update column data type postgres
SQL
0 vote147 views1 answer
Mysqli last row
SQL
0 vote101 views2 answers
Delete the last item in a table sql
SQL
0 vote135 views1 answer
Criteria builder select subset of column
SQL
1 vote135 views1 answer
Flask sqlalchemy filter multiple conditions
SQL
1 vote141 views1 answer
Declare variables sql
SQL
1 vote129 views1 answer
Mysql how to reset primary key
SQL
1 vote173 views2 answers
Sql split string by space
SQL
12 votes130 views2 answers
Select into insert sql server
SQL