/Python/Invalid literal for int() with base 10 python

Invalid literal for int() with base 10 python

#another way is to check if the entered number isdigit()
#that way you will ensure unhandled exception incase of erroneus data

number= input("What is your weight:")
if number.isdigit():
    kilos=int(float(number))
    print ("The weight of the person is:" + str(kilos))
else:
    print("Error - Please enter a proper weight")

Source: itsmycode.com

Similar codes

0 vote173 views2 answers
Sort list of string datetimes python
Python
0 vote131 views1 answer
Django trim string whitespace
Python
2 votes186 views1 answer
Tkinter label textvariable example
Python
0 vote188 views1 answer
Crear ondas segun musica python
Python
0 vote178 views1 answer
Python string equals
Python
1 vote174 views2 answers
How to find the shortest word in a list python
Python
0 vote185 views1 answer
Create virtual environments python
Python
5 votes180 views2 answers
Hide console in python build
Python
0 vote229 views1 answer
Python how to request query string korean encode
Python
1 vote176 views1 answer
Read shp in python
Python