/Python/Invalid literal for int() with base 10 python

Invalid literal for int() with base 10 python

#another way is to check if the entered number isdigit()
#that way you will ensure unhandled exception incase of erroneus data

number= input("What is your weight:")
if number.isdigit():
    kilos=int(float(number))
    print ("The weight of the person is:" + str(kilos))
else:
    print("Error - Please enter a proper weight")

Source: itsmycode.com

Similar codes

0 vote157 views1 answer
Check if timestamp is NaT
Python
0 vote99 views1 answer
Removing even rows in pandas
Python
22 votes143 views4 answers
Python is float
Python
41 votes150 views6 answers
Youtube.com
Python
1 vote174 views2 answers
Flask console log
Python Flask
3 votes139 views1 answer
Pyautogui moveTo overtime
Python
3 votes146 views2 answers
Pyperclip copy paste
Python
0 vote141 views1 answer
Transform networkx graph to dataframe
Python
1 vote227 views2 answers
Convertir datetime to timestamp django
Python Django
0 vote129 views3 answers
Join list with comma python
Python