Balancing paranthesis python

o=['[','{','(']
c=[']','}',')']

def check(s):
    a=[]
    for i in s:
       
        if i in o:
             a.append(i)
        elif i in c:
            pos=c.index(i)
            if((len(a)>0)and(o[pos]==a[len(a)-1])):
                a.pop()
            else:
                return "Unbalaced"
    if len(a)==0:
        return "bal"
    else:
        return "Unbal"
            

s='{{[])}}'
string=check(s)
print(string)

Similar codes

2 votes164 views2 answers
Combination without repetition python
Python
5 votes169 views2 answers
2 numbers after comma python
Python
0 vote164 views1 answer
Grepper how to use fraction
Python
0 vote164 views1 answer
Rename rows pandas based on condiions
Python
7 votes189 views3 answers
Convert uppercase to lowercase and vice versa in python
Python
31 votes225 views6 answers
Python strip whitespace
Python
1 vote119 views1 answer
Pandas return index
Python
0 vote184 views2 answers
Groupby fillna ffill
Python
2 votes155 views3 answers
Numpy random
Python
1 vote178 views1 answer
Previous value list loop python
Python