/Python/Python call function that need args with decorator

Python call function that need args with decorator

Python decorator *args **kwargs

from functools import wraps

def my_decorator(f):
    @wraps(f)
    def wrapper(*args, **kwargs):
        print('Calling decorated function')
        return f(*args, **kwargs)
    return wrapper

Python call function that need args with decorator

@decorator
def foo(*args, **kwargs):
    pass
# translates to

foo = decorator(foo)
# So if the decorator had arguments,

@decorator_with_args(arg)
def foo(*args, **kwargs):
    pass
# translates to

foo = decorator_with_args(arg, foo)

Similar codes

0 vote162 views1 answer
Take screenshot of video python
Python
0 vote171 views1 answer
Displace items in array python
Python
7 votes165 views2 answers
Python list 1 to n
Python
5 votes342 views2 answers
How does HTTPServer work in python
Python
0 vote158 views1 answer
How to close opened file in python
Python
1 vote154 views3 answers
Check if number is between two numbers python
Python
23 votes357 views2 answers
Flask or django
Python Django
2 votes199 views1 answer
Python gui drag and drop
Python
0 vote152 views1 answer
Brainf**k Interpreter in Python
Python
0 vote238 views1 answer
Are there learning activities for django-debug-toolbar
Python Django