Leap year formula

$day = [ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ];
$year = 2021;

if (($year % 4 == 0 && $year % 100 != 0) || ($year % 400 == 0)) {
  $day = [ 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ];
  echo "This is leap year - get 366 day";
  
} else {
   echo "This is NOT leap year - get ONLY 365 day";
}

Calculate if year is leap year

if (i%4==0 && i%100!=0 || i%400==0) {
months[2] = 29;
}
else {
month[2] = 28;
}

Leap year

import calendar

def is_leap(year):
    return calendar.isleap(year)

-1

Source: hackerrank.com

Similar codes

14 votes322 views5 answers
Wordpress get post thumbnail url
PHP Wordpress
1 vote194 views1 answer
Laravel dynamic page title
PHP Laravel
1 vote162 views1 answer
Calculate person age by birthdate php
PHP
0 vote256 views1 answer
Javascript in a php variable
PHP
-1 vote194 views1 answer
PHP Warning: require(/Applications/Ampps/www/SalesSystem/vendor/composer/../symfony/polyfill-php80/bootstrap.php): failed to open stream: No such file or directory in /Applications/Ampps/www/SalesSystem/vendor/composer/autoload_real.php on line 66
PHP
0 vote155 views1 answer
How convert the string to int in laravel function event
PHP Laravel
0 vote171 views1 answer
Php array form
PHP
0 vote294 views1 answer
Zend Framework 2 in a ZF1 project
PHP Zend
0 vote231 views2 answers
Bigtext migration laravel
PHP Laravel
0 vote246 views1 answer
Meyfa/phpunit-assert-gd[v2.0.0, ..., v2.x-dev, v3.0.0] require ext-gd * -> it is missing from your system. Install or enable PHP's gd extension
PHP