/Python/Numpy.dot

Numpy.dot

Numpy.dot

np.dot([2j, 3j], [2j, 3j])
(-13+0j)

0

Source: numpy.org

Numpy.dot

np.dot(3, 4)
12

0

Source: numpy.org

Numpy.dot

a = [[1, 0], [0, 1]]
>>> b = [[4, 1], [2, 2]]
>>> np.dot(a, b)
array([[4, 1],
       [2, 2]])

0

Source: numpy.org

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