/Python/Python get index of first element of list that matches condition

Python get index of first element of list that matches condition

# Find first index (or value) that meets condition
my_list = [2, 4, 6, 9, 10]

# Option 1. Use an iterator (does not scan all list)
y = (i for i,x in enumerate(my_list) if is_odd(x))
idx1 = next(y)  # <== index of first element

y = (x for i,x in enumerate(my_list) if is_odd(x))
v1 = next(y)  # <== value of first element


# Option 2. Use a list comprehension (scans all list)
idx1 = [i for i,x in enumerate(my_list) if x % 2 != 0][0]
v1 = [x for i,x in enumerate(my_list) if x % 2 != 0][0]

Similar codes

9 votes129 views5 answers
How to make a window in pygame
Python
1 vote128 views1 answer
Boolean python meaning for idiots
Python
0 vote133 views1 answer
Find optimal number of clusters sklearn
Python
1 vote194 views2 answers
Conda import django
Python Django
0 vote137 views1 answer
OfficeApi
Python
33 votes141 views2 answers
Este año spanish meaning
Python
0 vote181 views2 answers
Numpy softmax
Python
0 vote150 views1 answer
Heroku[web.1]: Process exited with status 3
Python
2 votes148 views1 answer
How to rewrite minute in datetime python
Python
0 vote139 views1 answer
Cptac dataset
Python