/SQL/How to get second highest salary in each department in sql

How to get second highest salary in each department in sql

SELECT E.Employers_name, E.dep_number, E.salary
FROM Employers E
WHERE 1 = (SELECT COUNT(DISTINCT salary) 
        FROM Employers B 
        WHERE B.salary > E.salary AND E.dep_number = B.dep_number)
group by E.dep_number

Sql find second highest salary employee

/* sql 2nd highest salary employee */
select sal, ename
from emp
where sal =
    (
        select max(sal) from emp where sal <
            (select max(sal) from emp)
    )
----------------------------------------------- option 2
select *
from 
(
    select ename, sal, dense_rank() over(order by sal desc) rank
    from emp
)
where rank =2;

Get max salary from each department sql

--Find out the name of top earner in each departments
--Output has Name, Department name and max salary of the department

SELECT E.FIRST_NAME , D.DEPARTMENT_NAME, E.SALARY
FROM EMPLOYEES E
JOIN DEPARTMENTS D ON E.DEPARTMENT_ID = D.DEPARTMENT_ID
WHERE SALARY IN(SELECT MAX(E.SALARY)
FROM EMPLOYEES E
JOIN DEPARTMENTS D ON E.DEPARTMENT_ID = D.DEPARTMENT_ID
GROUP BY DEPARTMENT_NAME);

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