Open link c#

System.Diagnostics.Process.Start("http://google.com");

Open url in c#

var uri = "https://www.google.com";
var psi = new System.Diagnostics.ProcessStartInfo();
psi.UseShellExecute = true;
psi.FileName = uri;
System.Diagnostics.Process.Start(psi);

Similar codes

0 vote269 views1 answer
System.InvalidOperationException: No owin.Environment item was found in the context.
C#
1 vote212 views1 answer
Unity raycast all layers except one
C#
28 votes186 views2 answers
C# file exist
C#
5 votes256 views1 answer
Unity how to get fps c#
C#Unity
1 vote260 views1 answer
How to set serial number in gridview in asp net
C#
7 votes221 views1 answer
Random value in array c#
C#
2 votes185 views5 answers
C# enum
C#
26 votes192 views1 answer
Google drive c#
C#
0 vote199 views1 answer
C# datetime remove days
C#
0 vote200 views1 answer
C# string right extension
C#