Django group by

# If you mean to do aggregation you can use the aggregation features of the ORM:
from django.db.models import Count
Members.objects.values('designation').annotate(dcount=Count('designation'))

# This results in a query similar to:
SELECT designation, COUNT(designation) AS dcount
FROM members GROUP BY designation

#and the output would be of the form
[{'designation': 'Salesman', 'dcount': 2}, 
 {'designation': 'Manager', 'dcount': 2}]

Source: stackoverflow.com

Similar codes

0 vote175 views2 answers
How to get current page url in django template
Python Django
1 vote198 views1 answer
How to migrate from sqlite to postgresql django
Python Django
0 vote199 views2 answers
Set environment variable heroku django
Python Django
0 vote178 views1 answer
How to add value in array django
Python Django
0 vote213 views1 answer
Django populate database in view
Python Django
0 vote285 views5 answers
Django-tool-bar
Python Django
0 vote181 views1 answer
Check this id exist in database django
Python Django
9 votes189 views2 answers
Django model form import
Python Django
0 vote186 views1 answer
Django update request.post
Python Django
1 vote188 views1 answer
Counter in django template
Python Django