Django group by

# If you mean to do aggregation you can use the aggregation features of the ORM:
from django.db.models import Count
Members.objects.values('designation').annotate(dcount=Count('designation'))

# This results in a query similar to:
SELECT designation, COUNT(designation) AS dcount
FROM members GROUP BY designation

#and the output would be of the form
[{'designation': 'Salesman', 'dcount': 2}, 
 {'designation': 'Manager', 'dcount': 2}]

Source: stackoverflow.com

Similar codes

0 vote105 views1 answer
Get value of variable in session django
Python Django
0 vote165 views1 answer
Django BruteBuster error failed attempts
Python Django
0 vote118 views1 answer
HTTP Error 403: Forbidden django account signup email
Python Django
30 votes280 views3 answers
Django createsuperuser
Python Django
0 vote178 views1 answer
Redirect a post request django
Python Django
0 vote169 views1 answer
Django create object with default today date
Python Django
0 vote180 views1 answer
Django.core.exceptions.FieldError: 'date' cannot be specified for Forum model form as it is a non-editable field
Python Django
0 vote123 views1 answer
Python django if key exists
Python Django
2 votes188 views1 answer
How store list in django session
Python Django
0 vote168 views1 answer
Django file upload this field is required
Python Django