Django group by

# If you mean to do aggregation you can use the aggregation features of the ORM:
from django.db.models import Count
Members.objects.values('designation').annotate(dcount=Count('designation'))

# This results in a query similar to:
SELECT designation, COUNT(designation) AS dcount
FROM members GROUP BY designation

#and the output would be of the form
[{'designation': 'Salesman', 'dcount': 2}, 
 {'designation': 'Manager', 'dcount': 2}]

Source: stackoverflow.com

Similar codes

5 votes308 views1 answer
Q is not defined pylance django
Python Django
0 vote234 views1 answer
Initial TypedMultipleChoiceField django
Python Django
0 vote228 views1 answer
Django queryset last 10
Python Django
0 vote198 views1 answer
Python django if key exists
Python Django
0 vote339 views1 answer
Django 3 create async rest api
Python Django
0 vote242 views1 answer
Django serializer get image list
Python Django
0 vote235 views2 answers
Django get all models
Python Django
1 vote255 views1 answer
Getting multiple selected value django
Python Django
0 vote252 views3 answers
User serializer in django rest framework
Python Django
0 vote272 views1 answer
Else if in django template
Python Django