Sql datediff month

CREATE FUNCTION FullMonthsSeparation 
(
    @DateA DATETIME,
    @DateB DATETIME
)
RETURNS INT
AS
BEGIN
    DECLARE @Result INT

    DECLARE @DateX DATETIME
    DECLARE @DateY DATETIME

    IF(@DateA < @DateB)
    BEGIN
        SET @DateX = @DateA
        SET @DateY = @DateB
    END
    ELSE
    BEGIN
        SET @DateX = @DateB
        SET @DateY = @DateA
    END

    SET @Result = (
                    SELECT 
                    CASE 
                        WHEN DATEPART(DAY, @DateX) > DATEPART(DAY, @DateY)
                        THEN DATEDIFF(MONTH, @DateX, @DateY) - 1
                        ELSE DATEDIFF(MONTH, @DateX, @DateY)
                    END
                    )

    RETURN @Result
END
GO

SELECT dbo.FullMonthsSeparation('2009-04-16', '2009-05-15') as MonthSep -- =0
SELECT dbo.FullMonthsSeparation('2009-04-16', '2009-05-16') as MonthSep -- =1
SELECT dbo.FullMonthsSeparation('2009-04-16', '2009-06-16') as MonthSep -- =2

Source: stackoverflow.com

Similar codes

0 vote340 views2 answers
Create new table from existing table with data in sql server
SQL
7 votes189 views2 answers
Oracle sql drop index
SQL
2 votes190 views1 answer
Oracle index size
SQL
25 votes213 views6 answers
Import database mysql command line
SQL
0 vote174 views1 answer
Python mysql query where
SQL
0 vote223 views1 answer
Sql tablo sp
SQL
2 votes306 views2 answers
MySql FULL OUTER JOIN
SQL
2 votes206 views1 answer
Sql skip the first row
SQL
0 vote174 views1 answer
Select all tables linked server sql
SQL
0 vote228 views1 answer
Postgresql select fast check no rows
SQL