Django queryset group by

Django group by

# If you mean to do aggregation you can use the aggregation features of the ORM:
from django.db.models import Count
Members.objects.values('designation').annotate(dcount=Count('designation'))

# This results in a query similar to:
SELECT designation, COUNT(designation) AS dcount
FROM members GROUP BY designation

#and the output would be of the form
[{'designation': 'Salesman', 'dcount': 2}, 
 {'designation': 'Manager', 'dcount': 2}]

Source: stackoverflow.com

Similar codes

29 votes307 views5 answers
Static dirs django
Python Django
2 votes196 views3 answers
Django login required decorator
Python Django
0 vote195 views1 answer
Django today date in template
Python Django
0 vote183 views1 answer
Django created at field
Python Django
15 votes223 views4 answers
Q django
Python Django
0 vote167 views1 answer
Get list of users django
Python Django
0 vote276 views1 answer
Django show image in admin page
Python Django
0 vote203 views1 answer
Django or
Python Django
0 vote189 views1 answer
Django model get field verbose name
Python Django
0 vote199 views1 answer
Django retrieveupdatedestroyapiview
Python Django