One2many add tuple

(0, 0,  { values })    link to a new record that needs to be created with the given values dictionary
(1, ID, { values })    update the linked record with id = ID (write *values* on it)
(2, ID)                remove and delete the linked record with id = ID (calls unlink on ID, that will delete the object completely, and the link to it as well)
(3, ID)                cut the link to the linked record with id = ID (delete the relationship between the two objects but does not delete the target object itself)
(4, ID)                link to existing record with id = ID (adds a relationship)
(5)                    unlink all (like using (3,ID) for all linked records)
(6, 0, [IDs])          replace the list of linked IDs (like using (5) then (4,ID) for each ID in the list of IDs)

Source: stackoverflow.com

Similar codes

0 vote208 views1 answer
Python regions
Python
1 vote210 views1 answer
Python module install a whl
Python
2 votes188 views1 answer
How to multiply a string in python
Python
0 vote189 views2 answers
Python normalized correlation
Python
73 votes187 views6 answers
Remove duplicates python
Python
0 vote266 views1 answer
Discord.py how to print audit logs
Python
0 vote224 views1 answer
Best way to access nested key in python
Python
1 vote187 views3 answers
Python sort list by custom function
Python
24 votes182 views6 answers
Django update model
Python
1 vote224 views1 answer
Django form list option
Python Django