/Python/Square of numbers in non-decreasing order

Square of numbers in non-decreasing order

"""
Given an integer array sorted in non-decreasing order, return an array of the squares of each number sorted in
non-decreasing order.
"""


def sortedSquares(nums):
    n = len(nums)
    start, end = 0, n - 1
    result = [0] * n
    index = n - 1

    while end > -1 and index > -1:
        if abs(nums[start]) > abs(nums[end]):
            result[index] = nums[start] ** 2
            start += 1
        else:
            result[index] = nums[end] ** 2
            end -= 1
        index -= 1

    return result


print(sortedSquares([-4, -3, -2, 0, 1, 2, 5, 10]))

Source: raw.githubusercontent.com

Similar codes

0 vote190 views1 answer
Menu with icons tkinter
Python
0 vote232 views1 answer
For loop with zip and enumerate
Python
0 vote211 views3 answers
2 decimal places
Python
0 vote252 views1 answer
Sqlite3 python parameterized query
Python
0 vote239 views1 answer
Sin , Cos Graph using python turtle.
Python
0 vote190 views1 answer
Find & replace in csv file
Python
0 vote272 views1 answer
Transform jpg image into array for conv2d
Python
1 vote327 views1 answer
Create django group
Python Django
1 vote270 views1 answer
Flask api with parameter
Python Flask
20 votes197 views5 answers
List directory in python
Python