/Python/Take first n row of dictionary python

Take first n row of dictionary python

a_dictionary = {"name" : "John", "age" : 35, "height" : 65}

dict_items = a_dictionary.items()

first_two = list(dict_items)[:2]
print(first_two)

OUTPUT
[('name', 'John'), ('age', 35)]

first_three = list(dict_items)[:3]
print(first_three)

OUTPUT
[('name', 'John'), ('age', 35), ('height', 65)]

Similar codes

0 vote141 views1 answer
Menu extension in mit app inventor
Python
0 vote168 views1 answer
ConversionofDatatypes-I
Python
26 votes181 views4 answers
Copy text python
Python
15 votes154 views3 answers
Max int python
Python
0 vote141 views1 answer
How to remove role from people with a reaction discord bot python
Python
63 votes188 views4 answers
Python find in string
Python
0 vote164 views1 answer
How to import discord in python rewrite vscode
Python
1 vote148 views1 answer
How to re run code in python
Python
26 votes138 views6 answers
Square root in python
Python
1 vote154 views1 answer
Flask clear session
Python