R select column names starting with

#  Data
df <- data.frame( ABC_1 = runif(3),
            ABC_2 = runif(3),
            XYZ_1 = runif(3),
            XYZ_2 = runif(3) )

#      ABC_1     ABC_2     XYZ_1     XYZ_2
#1 0.3792645 0.3614199 0.9793573 0.7139381
#2 0.1313246 0.9746691 0.7276705 0.0126057
#3 0.7282680 0.6518444 0.9531389 0.9673290

#  Use grepl
df[ , grepl( "ABC" , names( df ) ) ]
#      ABC_1     ABC_2
#1 0.3792645 0.3614199
#2 0.1313246 0.9746691
#3 0.7282680 0.6518444

#  grepl returns logical vector like this which is what we use to subset columns
grepl( "ABC" , names( df ) )
#[1]  TRUE  TRUE FALSE FALSE

Source: stackoverflow.com

Similar codes

3 votes471 views2 answers
If string in r
R
0 vote210 views1 answer
Error installing devtools r
R
0 vote194 views1 answer
ISO 2 letter country code in r
R
0 vote187 views1 answer
R reverse vector
R
0 vote231 views1 answer
How to change the font of the xlab in plot in r
R
0 vote280 views1 answer
Rstudio github upload
R
0 vote138 views1 answer
Gradient background ggplot
R
-1 vote204 views2 answers
How to count unique values in r
R
1 vote180 views1 answer
Paste no space r
R
3 votes250 views2 answers
Find average in r
R