Free the Bunny Prisoners

from itertools import combinations


def solution(num_buns, num_required):
    keyrings = [[] for num in range(num_buns)]
    copies_per_key = num_buns - num_required + 1
    for key, bunnies in enumerate(combinations(range(num_buns), copies_per_key)):
        for bunny in bunnies:
            keyrings[bunny].append(key)

    return keyrings


if __name__ == "__main__":
    assert all([all([x == y for x, y in zip(a, b)])
                for a, b in zip([[0, 1, 2, 3, 4, 5], [0, 1, 2, 6, 7, 8], [0, 3, 4, 6, 7, 9], [1, 3, 5, 6, 8, 9], [2, 4, 5, 7, 8, 9]], solution(5, 3))])
    assert all([all([x == y for x, y in zip(a, b)])
                for a, b in zip([[0], [1], [2], [3]], solution(4, 4))])

Similar codes

0 vote130 views1 answer
User_info = user_info.save(commit=False)
Python
0 vote130 views3 answers
Split credit card number python
Python
0 vote138 views1 answer
Command run test keep db python
Python
0 vote174 views1 answer
Removing duplicates using json python
Python
24 votes155 views3 answers
Get last n characters of string python
Python
0 vote136 views1 answer
Python string iterate 3 characters at a time
Python
1 vote163 views1 answer
How to get all folders on path in python
Python
3 votes95 views1 answer
Parquet to csv
Python
2 votes176 views2 answers
Python !=
Python
0 vote138 views1 answer
Python on read text execute command
Python