Free the Bunny Prisoners

from itertools import combinations


def solution(num_buns, num_required):
    keyrings = [[] for num in range(num_buns)]
    copies_per_key = num_buns - num_required + 1
    for key, bunnies in enumerate(combinations(range(num_buns), copies_per_key)):
        for bunny in bunnies:
            keyrings[bunny].append(key)

    return keyrings


if __name__ == "__main__":
    assert all([all([x == y for x, y in zip(a, b)])
                for a, b in zip([[0, 1, 2, 3, 4, 5], [0, 1, 2, 6, 7, 8], [0, 3, 4, 6, 7, 9], [1, 3, 5, 6, 8, 9], [2, 4, 5, 7, 8, 9]], solution(5, 3))])
    assert all([all([x == y for x, y in zip(a, b)])
                for a, b in zip([[0], [1], [2], [3]], solution(4, 4))])

Similar codes

1 vote135 views1 answer
Python extract name out of mail
Python
0 vote141 views2 answers
Check status code urllib
Python
0 vote174 views1 answer
How to input a string in streamlit
Python
2 votes137 views1 answer
Np logical_or
Python
5 votes143 views4 answers
Dropping unnamed columns in pandas
Python
0 vote130 views1 answer
Python search list by value
Python
0 vote141 views1 answer
Threshhold crossing on list python
Python
0 vote166 views1 answer
Django test imagefield
Python
0 vote89 views1 answer
Django templates directory
Python
0 vote162 views1 answer
How to make ui dialog pop in front pyqt
Python