Free the Bunny Prisoners

from itertools import combinations


def solution(num_buns, num_required):
    keyrings = [[] for num in range(num_buns)]
    copies_per_key = num_buns - num_required + 1
    for key, bunnies in enumerate(combinations(range(num_buns), copies_per_key)):
        for bunny in bunnies:
            keyrings[bunny].append(key)

    return keyrings


if __name__ == "__main__":
    assert all([all([x == y for x, y in zip(a, b)])
                for a, b in zip([[0, 1, 2, 3, 4, 5], [0, 1, 2, 6, 7, 8], [0, 3, 4, 6, 7, 9], [1, 3, 5, 6, 8, 9], [2, 4, 5, 7, 8, 9]], solution(5, 3))])
    assert all([all([x == y for x, y in zip(a, b)])
                for a, b in zip([[0], [1], [2], [3]], solution(4, 4))])

Similar codes

5 votes108 views2 answers
Break all loops
Python
3 votes108 views2 answers
Python element wise multiplication list
Python
0 vote114 views1 answer
Python "urllib3" download and save pdf
Python
0 vote118 views1 answer
Relative text size put text cv2
Python
0 vote101 views1 answer
To the power python markdown
Python
0 vote97 views1 answer
Python second element of every tuple in list
Python
0 vote104 views2 answers
Disable network on pytest
Python
0 vote107 views1 answer
Create dictionary python having hash value
Python
3 votes96 views2 answers
Scapy python functions
Python
0 vote108 views1 answer
Install sort
Python