/SQL/How to get the date diff on once field in sql server

How to get the date diff on once field in sql server

SELECT t1.OrderNo,DATEDIFF(day,t1.LoadedStartDate,t2.LoadedStartDate)
FROM UnnamedTableFromQuestion t1
       INNER JOIN
     UnnamedTableFromQuestion t2
       on
         t1.OrderNo = t2.OrderNo
WHERE t1.OpNo = 1 and
      t2.OpNo = 4
      
////////////////////////////////////////////////////////////////

select cur.unique_id_field, cur.seq_no, cur.date_created ,

  datediff(second, prv.date_created, cur.date_created) as diff_in_seconds

from yourtable as cur

  join yourtable as prv

    on cur.seq_no = prv.seq_no + 1;

Source: stackoverflow.com

Similar codes

0 vote201 views1 answer
Failed to connect to localhost:1433 - self signed certificate
SQL
3 votes202 views1 answer
Postgres add not null to existing column
SQL
1 vote191 views1 answer
Window function mysql
SQL
1 vote206 views1 answer
Blob datatype in mysql
SQL
0 vote203 views1 answer
List mysql tables and views
SQL
1 vote209 views1 answer
How to see all table partition in oracle
SQL
5 votes199 views2 answers
Oracle tables with column name
SQL
0 vote203 views1 answer
Python mysql query to dataframe
SQL
1 vote218 views1 answer
Oracle sequence last_number
SQL
1 vote228 views3 answers
How to create a table structure from another table in mysql
SQL