/SQL/How to get the date diff on once field in sql server

How to get the date diff on once field in sql server

SELECT t1.OrderNo,DATEDIFF(day,t1.LoadedStartDate,t2.LoadedStartDate)
FROM UnnamedTableFromQuestion t1
       INNER JOIN
     UnnamedTableFromQuestion t2
       on
         t1.OrderNo = t2.OrderNo
WHERE t1.OpNo = 1 and
      t2.OpNo = 4
      
////////////////////////////////////////////////////////////////

select cur.unique_id_field, cur.seq_no, cur.date_created ,

  datediff(second, prv.date_created, cur.date_created) as diff_in_seconds

from yourtable as cur

  join yourtable as prv

    on cur.seq_no = prv.seq_no + 1;

Source: stackoverflow.com

Similar codes

1 vote153 views1 answer
Alter add syntax
SQL
0 vote169 views1 answer
Load data infile mariadb slow
SQL
2 votes154 views1 answer
Mysql create user with mysql_native_password
SQL
5 votes143 views2 answers
Add column postgres with default value
SQL
2 votes151 views1 answer
Compare date in sql
SQL
1 vote145 views1 answer
Check constraint to check if date greater than todays date
SQL
2 votes200 views1 answer
Oracle Column Names of a table
SQL
0 vote137 views1 answer
Create table employees oracle
SQL
1 vote112 views1 answer
Mysql show attributes of a table
SQL
10 votes143 views4 answers
Primary key in sql
SQL