/Python/Global variable not accessible withing thread

Global variable not accessible withing thread

from threading import Thread
from queue import Queue
import time

def thread1(threadname, q):
    #read variable "a" modify by thread 2
    while True:
        a = q.get()
        if a is None: return # Poison pill
        print a

def thread2(threadname, q):
    a = 0
    for _ in xrange(10):
        a += 1
        q.put(a)
        time.sleep(1)
    q.put(None) # Poison pill

queue = Queue()
thread1 = Thread( target=thread1, args=("Thread-1", queue) )
thread2 = Thread( target=thread2, args=("Thread-2", queue) )

thread1.start()
thread2.start()
thread1.join()
thread2.join()

Source: stackoverflow.com

Similar codes

0 vote101 views1 answer
Lineplot in plt
Python
1 vote90 views1 answer
Python return right operand if left is falsy
Python
14 votes99 views6 answers
Python if condition
Python
0 vote104 views1 answer
Save image to file from URL
Python
9 votes108 views4 answers
Pandas print full dataframe
Python
0 vote100 views1 answer
For loop pattern in python stack overflow
Python
0 vote137 views1 answer
Fibonacci numbers in lamda python
Python
1 vote116 views1 answer
Python lock using a file
Python
39 votes110 views5 answers
How to calculate the sum of a list in python
Python
0 vote129 views1 answer
Pie auto percentage in python
Python