/Python/Global variable not accessible withing thread

Global variable not accessible withing thread

from threading import Thread
from queue import Queue
import time

def thread1(threadname, q):
    #read variable "a" modify by thread 2
    while True:
        a = q.get()
        if a is None: return # Poison pill
        print a

def thread2(threadname, q):
    a = 0
    for _ in xrange(10):
        a += 1
        q.put(a)
        time.sleep(1)
    q.put(None) # Poison pill

queue = Queue()
thread1 = Thread( target=thread1, args=("Thread-1", queue) )
thread2 = Thread( target=thread2, args=("Thread-2", queue) )

thread1.start()
thread2.start()
thread1.join()
thread2.join()

Source: stackoverflow.com

Similar codes

1 vote210 views1 answer
Print(int())
Python
0 vote181 views1 answer
Pillow rgb to grayscale
Python
0 vote216 views1 answer
How to install tkinter in pycharm
Python
1 vote179 views1 answer
How to get input from user in pyqt5
Python
0 vote196 views1 answer
Change size of image and fir it into numpy array opencv
Python
2 votes212 views3 answers
Find the Runner-Up Score!
Python
18 votes232 views3 answers
String Slices
Python
0 vote225 views1 answer
Install matplotlib.pyplot mac python 3
Python
0 vote194 views1 answer
Python division no remainder
Python
2 votes187 views1 answer
Python read xlsb pandas
Python