Make zipfile from directory py

Python zip folder

import shutil
shutil.make_archive(output_filename, 'zip', dir_name)

Source: stackoverflow.com

Python zip folder

import os
import zipfile

def zip_directory(folder_path, zip_path):
    with zipfile.ZipFile(zip_path, mode='w') as zipf:
        len_dir_path = len(folder_path)
        for root, _, files in os.walk(folder_path):
            for file in files:
                file_path = os.path.join(root, file)
                zipf.write(file_path, file_path[len_dir_path:])
                
zip_directory('C:/FolderToZip', 'C:/Folder.zip')

Make zipfile from directory py

import zipfile
filePaths = [] # Make an array string with all paths to files
for root, directories, files in os.walk("MyDirectoryPath"): # Scans for all subfolders and files in MyDirectoryPath
        for filename in files: # loops for every file
            filePath = os.path.join(root, filename) # Joins both the directory and the file name
            filePaths.append(filePath) # appends to the array
z = zipfile.ZipFile("MyDirectoryPathWithZipExt.zip", 'w')
with z:
    for file in filePaths: # Loops for all files in array
        z.write(file) # Writes file to MyDirectoryPathWithZipExt.zip

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