Python defaultdict to dict

>>> #You can simply call dict:
>>> a
defaultdict(<type 'list'>, {'1': ['b', 'a'], '3': ['b'], '2': ['a']})
>>> dict(a)
{'1': ['b', 'a'], '3': ['b'], '2': ['a']}

# but remember that a defaultdict is a dict
# (with some special behavior, check source):
>>> isinstance(a, dict)
True

Source: stackoverflow.com

Defaultdict python dict inside dict

nums = [1, 2, 1, 1, 4, -4, 2, 2, 4, 2, 5, 7]
dict_in_dict = defaultdict(dict)
for i in range(0, len(nums), 3):
    dict_in_dict[nums[i+1]][nums[i]] = -1*nums[i+2]
dict(dict_in_dict)

# result
# {2: {1: -1, 2: -4}, 4: {1: 4}, 5: {2: -7}}

Similar codes

0 vote162 views1 answer
Django send_mail not working in testcase
Python
1 vote182 views2 answers
Django queryset unique values
Python Django
0 vote139 views1 answer
Install opentracing in python
Python
0 vote141 views1 answer
Random point seeds within a cyircle python
Python
0 vote135 views1 answer
Opencv skip video frames
Python
0 vote195 views1 answer
Django force download file
Python
2 votes155 views1 answer
Pycharm why won't os work
Python
0 vote126 views1 answer
Calculate time python
Python
0 vote142 views1 answer
Newrelic api for Tags
Python
-2 votes172 views1 answer
How to get the user argent in django
Python Django