Python list safely pop

In [1]: from typing import List, Any

In [2]: x = [{"count": 100}, {"count": 30}]
# use this function
In [3]: def defaultable_pop(input_list: List, index: int, default_value: Any = None) -> Any:
   ...:     try:
   ...:         return input_list.pop(index)
   ...:     except IndexError:
   ...:         return default_value
   ...:
#								list, index, (default of empty dict)
In [4]: y: int = defaultable_pop(x, 0, dict({})).get("count", 0)

In [5]: y
Out[5]: 100

# As opposed to:
# y: int = x[0].get("count", 0) if len(x) > 0 else 0

Similar codes

11 votes176 views2 answers
How to send whatsapp message with python
Python
0 vote146 views2 answers
Random array in python
Python
0 vote155 views1 answer
Boxplot label python
Python
0 vote156 views1 answer
Python import module with minus in its name
Python
0 vote157 views1 answer
Back of list
Python
0 vote151 views1 answer
Screen size tkinter
Python
3 votes133 views1 answer
Get range of items of python list
Python
0 vote108 views2 answers
Smooth interpolation python
Python
5 votes226 views3 answers
How to run flask in port 80
Python Flask
6 votes141 views1 answer
Python check if number
Python