Python list safely pop

In [1]: from typing import List, Any

In [2]: x = [{"count": 100}, {"count": 30}]
# use this function
In [3]: def defaultable_pop(input_list: List, index: int, default_value: Any = None) -> Any:
   ...:     try:
   ...:         return input_list.pop(index)
   ...:     except IndexError:
   ...:         return default_value
   ...:
#								list, index, (default of empty dict)
In [4]: y: int = defaultable_pop(x, 0, dict({})).get("count", 0)

In [5]: y
Out[5]: 100

# As opposed to:
# y: int = x[0].get("count", 0) if len(x) > 0 else 0

Similar codes

0 vote185 views1 answer
How to load multiple list of dictionary values which is stored in python file and load into another python file in python over loop
Python
0 vote194 views2 answers
Try except in list comprehension
Python
1 vote209 views1 answer
How to merge dataframe with different keys
Python
0 vote184 views1 answer
TemplateSyntaxError
Python
2 votes261 views2 answers
Python exception element not found
Python
0 vote191 views5 answers
Python trace table generator
Python
4 votes185 views4 answers
Python hex
Python
1 vote197 views1 answer
How to define dtype of each column before actually reading csv file
Python
34 votes258 views6 answers
Python if in list
Python
0 vote184 views1 answer
How make aloop in python
Python