Python list safely pop

In [1]: from typing import List, Any

In [2]: x = [{"count": 100}, {"count": 30}]
# use this function
In [3]: def defaultable_pop(input_list: List, index: int, default_value: Any = None) -> Any:
   ...:     try:
   ...:         return input_list.pop(index)
   ...:     except IndexError:
   ...:         return default_value
   ...:
#								list, index, (default of empty dict)
In [4]: y: int = defaultable_pop(x, 0, dict({})).get("count", 0)

In [5]: y
Out[5]: 100

# As opposed to:
# y: int = x[0].get("count", 0) if len(x) > 0 else 0

Similar codes

0 vote165 views3 answers
How to draw dendrogram in python
Python
0 vote163 views1 answer
How to print stdout while processing the execution in python
Python
0 vote169 views1 answer
Random Hex Colors bar generator, python turtle
Python
0 vote170 views1 answer
Python selenium firefox handle ssl bypass
Python
0 vote161 views1 answer
Exception Value: Object of type User is not JSON serializable
Python
8 votes324 views3 answers
Add new column based on condition on some other column in pandas.
Python
1 vote168 views1 answer
What is the purpose of the judiciary
Python
-1 vote215 views2 answers
Ai assistant in python
Python
0 vote216 views1 answer
Unction which takes in a list of integers and returns a dictionary of the five number summary..
Python
2 votes182 views1 answer
DtypeWarning: Columns (47) have mixed types.Specify dtype option on import or set low_memory=False
Python