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Python sort the values in a dictionary

Sort dict by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

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Source: stackoverflow.com

Python sort the values in a dictionary

from operator import itemgetter
new_dict = sorted(data.items(), key=itemgetter(1))

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