Tkinter simple notification

from tkinter import *
from sys import exit
def popupError(s):
    popupRoot = Tk()
    popupRoot.after(2000, exit)
    popupButton = Button(popupRoot, text = s, font = ("Verdana", 12), bg = "yellow", command = exit)
    popupButton.pack()
    popupRoot.geometry('400x50+700+500')
    popupRoot.mainloop()

Source: stackoverflow.com

Similar codes

1 vote142 views3 answers
Creat and active python environment
Python
1 vote131 views1 answer
Declare empty array of complex type python
Python
1 vote148 views1 answer
Print(\'Test set predictions:\\n{}\'.format(y_pred))
Python
0 vote158 views2 answers
Python fork error
Python
0 vote129 views1 answer
How to test that an exception was raise using pytest
Python
0 vote175 views1 answer
Python inspect.getsource
Python
23 votes140 views3 answers
Django rest framework
Python
0 vote134 views1 answer
Python string color format
Python
8 votes136 views2 answers
List of single item repeated python
Python
0 vote126 views1 answer
Pythagorean theorem calc: find c, a=n
Python