/Python/Get the invite url of server disc.py

Get the invite url of server disc.py

@client.command(pass_context=True)
async def link(ctx):
    server = client.get_server("server_id")
    link = client.create_invite(destination=server,xkcd=True,max_age=0,max_uses=number)
    await client.say(link)
    #max_age=0-> Never expire link
    #max_uses-> limit to usage the link
    #xkcd-> The URL fragment used for the invite if it is human readable.

Source: stackoverflow.com

Similar codes

1 vote159 views1 answer
How to update a plot in tkinter\
Python
0 vote150 views1 answer
Append to an array in 1st place python
Python
6 votes166 views3 answers
Python moving average pandas
Python
0 vote155 views1 answer
How to pass primary key to url django
Python
0 vote172 views1 answer
Python dijkstra implementation stack
Python
0 vote106 views1 answer
Python count number of combinations
Python
0 vote165 views1 answer
Pandas recognize type from strings
Python
5 votes149 views1 answer
Dataframe unique values in each column
Python
0 vote161 views1 answer
Print elements without print function in python
Python
1 vote171 views1 answer
Creating an apis with python and flask
Python