Fizzbuzz python

def fizz_buzz(num):
    if num % 3 == 0 and num % 5 == 0:
        return "fizzBuzz"
    elif num % 3 == 0:
        return "fizz"
    elif num % 5 == 0:
        return "buzz"
    else:
        return num

Fizz buzz python

def fizz_buzz(input):
    if (input % 3 == 0) and (input % 5 == 0):
        return "FizzBuzz"
    if input % 3 == 0:
        return "Fizz"
    if input % 5 == 0:
        return "Buzz"
    else:
        return input


print(fizz_buzz(3))

Fizz buzz python

output = ""

for i in range(1, 101):
 
    if (i % 3 == 0):
        output += "Fizz"
    
    if (i % 5 == 0):
        output += "Buzz"
    
    elif (i % 3 != 0): 
        output += str(i)
    
    output += "\n" # Add a new line at the end of the output 

print(output)

Fizzbuzz python solution

  
for number in range(1, 101):
  if number % 3 == 0 and number % 5 == 0:
    print("FizzBuzz")
  if number % 3 == 0:
    print("Fizz")
  if number % 5 == 0:
    print("Buzz")
  else:
    print([number])

Fizzbuzz python

# FizzBuzz in one line. Impress ur boss
for i in range(21): print((int(i) % 3 == 0)*'Fizz' + (int(i) % 5 == 0)*'Buzz' or i)
  
# Any string multiplied by False will return nothing.
#																 - sabz

Fizzbuzz python

for i in range (1,101):
    print("Fizz"*(i%3<1)+(i%5<1)*"buzz" or i)

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