/Shell/Bash/Write a bash program to print a given number in reverse order

Write a bash program to print a given number in reverse order

n=123465
sd=0
rev=0
while [ $n -gt 0 ]
do
    sd=$(( $n % 10 ))
    rev=$(( $rev * 10 + $sd ))
    n=$(( $n / 10 ))
done
echo "Reverse number of entered digit is $rev"

Source: unix.stackexchange.com

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