Balanced string in java

	 public boolean isBalanced(String string) {
		HashMap<Character, Character> bracketMap = new HashMap<>();
		bracketMap.put('(', ')');
		bracketMap.put('[', ']');
		bracketMap.put('{', '}');
		
		Stack<Character> stack = new Stack<>();
		
		for(int count = 0; count < string.length(); count++) {
			char current = string.charAt(count);
			
			if(bracketMap.keySet().contains(current)) {
				stack.push(current);
			} else if(bracketMap.values().contains(current)) {
				if(!stack.empty() && bracketMap.get(stack.peek()) == current){
					stack.pop();
				} else {
					return false;
				}
			}
		}
		return stack.empty();
	}

Balanced string in java

    public static boolean checkBalanced(String check) {
        Stack<Character> S = new Stack<Character>();
        for(int a = 0; a < check.length(); a++){
            char let = check.charAt(a);
            if(let == '[' || let == '{' || let == '(')
                S.push(let);
            else if(let == ']' || let == '}' || let == ')')
            {
                if(S.empty())
                    return false;
                switch(let)
                {
                    // Opening square brace
                    case ']':
                        if (S.pop() != '[')
                            return false;
                        break;
                    // Opening curly brace
                    case '}':
                        if (S.pop() != '{')
                            return false;
                        break;
                    // Opening paren brace
                    case ')':
                        if (S.pop() != '(')
                            return false;
                        break;
                    default:
                        break;
                }
            }
        }
        if(S.empty())
            return true;
        return false;
    }

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