/Python/Python - count number of values without dupicalte in a second column values

Python - count number of values without dupicalte in a second column values

ID, domain
123, 'vk.com'
123, 'vk.com'
123, 'twitter.com'
456, 'vk.com'
456, 'facebook.com'
456, 'vk.com'
456, 'google.com'
789, 'twitter.com'
789, 'vk.com'

df = df.groupby('domain')['ID'].nunique()
print (df)

domain
'facebook.com'    1
'google.com'      1
'twitter.com'     2
'vk.com'          3

Source: stackoverflow.com

Similar codes

0 vote119 views1 answer
How to define number in python
Python
31 votes274 views6 answers
Django admin create superuser
Python Django
1 vote121 views1 answer
How many data types are specified to numeric values in python
Python
0 vote121 views1 answer
Assert_series_equal
Python
0 vote120 views1 answer
Files and exceptions not working python
Python
-3 votes139 views5 answers
Python 3.1 release date
Python
0 vote113 views1 answer
Waitress serve
Python
12 votes121 views6 answers
Python curl
Python
0 vote88 views1 answer
Concat list of strings python
Python
0 vote149 views1 answer
Python developer job description
Python