/Python/Find the sum of all the multiples of 3 or 5 below 1000 python

Find the sum of all the multiples of 3 or 5 below 1000 python

nums = [3, 5]

result = 0
for i in range(0,1000):
    if i%3 == 0 or i%5 == 0:
        result += i

print(result)

Source: stackoverflow.com

Sum of multiples of 3 or 5 python

total = []

for num in range(0,1001):
    if (num % 3 == 0) or (num % 5 == 0):
        total.append(num)
        
print(sum(total))

Sum of all the multiples of 3 or 5

const findSum = n => {
  let countArr = []
  
  for(let i = 0; i <= n; i++) if(i % 3 === 0 || i % 5 === 0) countArr.push(i) 
  return countArr.reduce((acc , curr) => acc + curr)
}
console.log(findSum(5))

-1

Similar codes

0 vote208 views1 answer
Use latest file on aws s3 bucket python
Python
0 vote279 views1 answer
Django retrieveupdatedestroyapiview
Python
2 votes192 views1 answer
Scikit learn decision tree12
Python
0 vote197 views1 answer
Binary to decimal python
Python
0 vote194 views2 answers
Tinydb delete record
Python
8 votes217 views3 answers
Join dataframe pandas by column
Python
0 vote241 views1 answer
How to order randomly in django orm
Python
0 vote231 views1 answer
Backend not found Request Method: GET Request URL: http://127.0.0.1:8000/oauth/login/google-oauth2/ Raised by: social_django.views.au
Python Django
1 vote199 views2 answers
Remove a first array of item in python
Python
0 vote191 views1 answer
S=0 def sum(x,y): n=int(input("enter no. of terms") for i in range(n): l=int(input("enter no.")) s=s+l print(s) sum()
Python