Python numpy bbox

def bbox1(img):
    a = np.where(img != 0)
    bbox = np.min(a[0]), np.max(a[0]), np.min(a[1]), np.max(a[1])
    return bbox

def bbox2(img):
    rows = np.any(img, axis=1)
    cols = np.any(img, axis=0)
    rmin, rmax = np.where(rows)[0][[0, -1]]
    cmin, cmax = np.where(cols)[0][[0, -1]]

    return rmin, rmax, cmin, cmax

Source: stackoverflow.com

Similar codes

4 votes231 views5 answers
Min max python
Python
0 vote126 views1 answer
Find the item with the maximum number of occurrences in a list in Python
Python
-1 vote195 views3 answers
ValueError: If using all scalar values, you must pass an index
Python
0 vote117 views1 answer
Python close a socket
Python
1 vote120 views1 answer
Open excel through python
Python
0 vote119 views1 answer
Rasperry pi camera
Python
77 votes127 views6 answers
Python version
Python
0 vote177 views1 answer
Docker-compose.yml for flask celery rabbitmq
Python
0 vote115 views1 answer
Numpy remove columns containing nan
Python
43 votes123 views1 answer
All caps alphabet as list
Python