Sort number in dynamo

import re

liste = IN[0]

def natural_sort(l): 
    convert = lambda text: int(text) if text.isdigit() else text.lower() 
    alphanum_key = lambda key: [ convert(c) for c in re.split('([0-9]+)', key) ] 
    return sorted(l, key = alphanum_key)

OUT = natural_sort(liste)

Source: forum.dynamobim.com

Similar codes

5 votes55 views1 answer
C# escape characters
C#
1 vote89 views1 answer
Clear gridview data in c#
C#
8 votes102 views2 answers
C# round to 2 decimal places
C#
0 vote95 views1 answer
40/100 percentage
C#
24 votes99 views4 answers
Dictionary c# iterate
C#
13 votes94 views3 answers
How to use console in c#
C#
6 votes99 views1 answer
Unity rotate vector
C#
0 vote95 views1 answer
Asp.net listbox disable selection
C#
9 votes98 views1 answer
C# return two variables of different types
C#
0 vote210 views1 answer
C# remove all items from list where item value is null
C#