/Python/Python - sort dictionary by value

Python - sort dictionary by value

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Python - sort dictionary by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}

# Sort
a = sorted(d.items(), key=lambda x: x[1])

# Reverse sort
r = sorted(d.items(), key=lambda x: x[1], reverse=True)

Source: stackoverflow.com

Sort dictionary by values

from collections import OrderedDict
dd = OrderedDict(sorted(d.items(), key=lambda x: x[1]))
print(dd)

Source: thomas-cokelaer.info

Similar codes

0 vote139 views1 answer
Python regeression line
Python
0 vote141 views1 answer
Sum the items of an array
Python
0 vote149 views1 answer
How to take input in python as string and convert into integer list
Python
0 vote154 views1 answer
Credential not provided when i try to sign up a new user django
Python
0 vote169 views1 answer
Get column or row of matrix array numpy python
Python
0 vote150 views1 answer
How to make a username system using python
Python
2 votes157 views4 answers
How to add column to np array
Python
4 votes157 views2 answers
Print \\ in python
Python
0 vote174 views1 answer
How to config django templates with pathlib
Python
136 votes164 views6 answers
Input function python
Python