/Python/Python - sort dictionary by value

Python - sort dictionary by value

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Python - sort dictionary by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}

# Sort
a = sorted(d.items(), key=lambda x: x[1])

# Reverse sort
r = sorted(d.items(), key=lambda x: x[1], reverse=True)

Source: stackoverflow.com

Sort dictionary by values

from collections import OrderedDict
dd = OrderedDict(sorted(d.items(), key=lambda x: x[1]))
print(dd)

Source: thomas-cokelaer.info

Similar codes

7 votes133 views2 answers
Python encode comment
Python
0 vote222 views1 answer
Bulk upload with dictionary or list in django moels
Python Django
0 vote142 views1 answer
Supercharged python
Python
2 votes135 views2 answers
How to add elements in a dictionary in python
Python
0 vote141 views1 answer
Hello world with a variable in python 3
Python
11 votes145 views6 answers
Pandas join two columns
Python
0 vote192 views1 answer
Flask extends two base.html
Python Flask
0 vote131 views1 answer
Python red table from pdf
Python
1 vote128 views3 answers
Plot python x axis range
Python
0 vote158 views1 answer
How to draw a square pygame
Python