/Python/Python - sort dictionary by value

Python - sort dictionary by value

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Python - sort dictionary by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}

# Sort
a = sorted(d.items(), key=lambda x: x[1])

# Reverse sort
r = sorted(d.items(), key=lambda x: x[1], reverse=True)

Source: stackoverflow.com

Sort dictionary by values

from collections import OrderedDict
dd = OrderedDict(sorted(d.items(), key=lambda x: x[1]))
print(dd)

Source: thomas-cokelaer.info

Similar codes

0 vote163 views1 answer
How to make python turn a list into a text file grapper
Python
20 votes168 views3 answers
Appending dataframes pandas
Python
0 vote127 views1 answer
Neo4j python
Python
1 vote169 views1 answer
Why is there a lot of numbers in python
Python
0 vote163 views1 answer
Get Dates Between Two Ranges
Python
0 vote156 views1 answer
Python add column with constant value
Python
0 vote188 views1 answer
Lamda in f string
Python
0 vote178 views1 answer
Python project pick text color according to background
Python
2 votes158 views1 answer
How do i print a list line by line in python
Python
0 vote189 views1 answer
Create requirements file and load it in new envirnment.
Python