/Python/Python - sort dictionary by value

Python - sort dictionary by value

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Python - sort dictionary by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}

# Sort
a = sorted(d.items(), key=lambda x: x[1])

# Reverse sort
r = sorted(d.items(), key=lambda x: x[1], reverse=True)

Source: stackoverflow.com

Sort dictionary by values

from collections import OrderedDict
dd = OrderedDict(sorted(d.items(), key=lambda x: x[1]))
print(dd)

Source: thomas-cokelaer.info

Similar codes

0 vote190 views1 answer
Add new dimension
Python
0 vote217 views1 answer
What does json.loads do
Python
1 vote208 views2 answers
Zip django template
Python Django
0 vote171 views1 answer
Python continue inner for loop
Python
2 votes152 views1 answer
Python short circuit
Python
0 vote180 views1 answer
How to import matplotlib.pyplo in python
Python
5 votes235 views4 answers
Python generator function
Python
0 vote182 views1 answer
Pygame pin to top
Python
0 vote172 views1 answer
Read from text file and append in list
Python
0 vote195 views1 answer
Python glob how to read all txt files in folder
Python