/Python/Sort list of dictionaries python

Sort list of dictionaries python

Sort list of dictionaries by key python

newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])

Sorting a dictionary in python

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Source: stackoverflow.com

Sort list of dictionaries python

unsorted_list = [{"key1":5, "key2":2}, {"key1":5, "key2":1}]
sorted_list = sorted(unsorted_list, key=lambda k: k["key2"])

Sort dictionary python

l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = dict(sorted(l.items(),key=lambda x:x[1],reverse=True))
print(d1) #output : {2: 60, 3: 50, 1: 40, 4: 30, 5: 20}
d2 = dict(sorted(l.items(),key=lambda x:x[1],reverse=False))
print(d2) #output : {5: 20, 4: 30, 1: 40, 3: 50, 2: 60}

Sort the dictionary in python

d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)

How to sort a dictionary py

orders = {
	'cappuccino': 54,
	'latte': 56,
	'espresso': 72,
	'americano': 48,
	'cortado': 41
}

sort_orders = sorted(orders.items(), key=lambda x: x[1], reverse=True)

for i in sort_orders:
	print(i[0], i[1])

Source: careerkarma.com

Similar codes

0 vote162 views1 answer
Applymap(lambda x: x.encode('unicode_escape'). decode('utf-8') if isinstance(x, str) else x)
Python
0 vote172 views1 answer
Python write value in next row of existing .text file
Python
0 vote179 views1 answer
Python docx title
Python
0 vote180 views1 answer
Math domain error python
Python
0 vote166 views1 answer
File "demo_indentation_test.py", line 2 print("Five is greater than two!") ^ IndentationError: expected an indented block
Python
15 votes169 views2 answers
Python check if variable is string
Python
0 vote169 views1 answer
Getting range lowest and highest values from np array
Python
1 vote200 views1 answer
Error popup in django not visible
Python Django
19 votes200 views6 answers
Add item to python list
Python
0 vote176 views1 answer
Python every other including first
Python