/C#/How to generate random letters in C#

How to generate random letters in C#

private static Random random = new Random();
public static string RandomString(int length)
{
    const string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
    return new string(Enumerable.Repeat(chars, length)
      .Select(s => s[random.Next(s.Length)]).ToArray());
}

Source: stackoverflow.com

Random character c#

//Random Uppercase letter:
Random rnd = new Random();            
int ascii_index = rnd.Next(65, 91); //ASCII character codes 65-90
char myRandomUpperCase = Convert.ToChar(ascii_index); //produces any char A-Z

//random lowercase letter:
Random rnd2 = new Random();            
int ascii_index2 = rnd2.Next(97, 123); //ASCII character codes 97-123
char myRandomLowerCase = Convert.ToChar(ascii_index2); //produces any char a-z

//Random letter irrespective of case: (search up "random number from 2 different ranges" for explanation)
int i = rnd.Next(1, 3) == 1 ? rnd.Next(65, 91) : rnd.Next(97, 123);
char anyLetter = Convert.ToChar(i);

Similar codes

0 vote105 views2 answers
Component dynamic vue
C#
1 vote108 views1 answer
Save method in asp.net
C#
39 votes99 views4 answers
Unity get all children
C#
0 vote109 views1 answer
Getstring
C#
10 votes97 views2 answers
Unity find gameobject by name
C#
0 vote132 views1 answer
How to make play button in unity
C#
0 vote89 views1 answer
C# switch statement
C#
0 vote122 views1 answer
Death transition unity 2d
C#
4 votes100 views3 answers
Email regex c#
C#
4 votes101 views2 answers
C# get desktop path
C#