/C#/How to generate random letters in C#

How to generate random letters in C#

private static Random random = new Random();
public static string RandomString(int length)
{
    const string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
    return new string(Enumerable.Repeat(chars, length)
      .Select(s => s[random.Next(s.Length)]).ToArray());
}

Source: stackoverflow.com

Random character c#

//Random Uppercase letter:
Random rnd = new Random();            
int ascii_index = rnd.Next(65, 91); //ASCII character codes 65-90
char myRandomUpperCase = Convert.ToChar(ascii_index); //produces any char A-Z

//random lowercase letter:
Random rnd2 = new Random();            
int ascii_index2 = rnd2.Next(97, 123); //ASCII character codes 97-123
char myRandomLowerCase = Convert.ToChar(ascii_index2); //produces any char a-z

//Random letter irrespective of case: (search up "random number from 2 different ranges" for explanation)
int i = rnd.Next(1, 3) == 1 ? rnd.Next(65, 91) : rnd.Next(97, 123);
char anyLetter = Convert.ToChar(i);

Similar codes

0 vote88 views1 answer
Dictionary namespace c#
C#
0 vote106 views1 answer
OnCollsionEnter layermask
C#
2 votes99 views5 answers
C# enum
C#
4 votes101 views3 answers
Unfreeze position in unity
C#
0 vote101 views2 answers
Change line color in c#
C#
0 vote91 views1 answer
Unity read from text file
C#
1 vote97 views1 answer
Unity 2d joystick controls
C#
1 vote142 views1 answer
Unity get script from gameobject
C#Unity
-1 vote98 views4 answers
Signalr
C#
0 vote134 views1 answer
Unity c# store gameobject in array
C#Unity