Print pattern a shape in python

result_str="";    
for row in range(0,7):    
    for column in range(0,7):     
        if (((column == 1 or column == 5) and row != 0) or ((row == 0 or row == 3) and (column > 1 and column < 5))):    
            result_str=result_str+"*"    
        else:      
            result_str=result_str+" "    
    result_str=result_str+"\n"    
print(result_str);

Similar codes

0 vote231 views1 answer
Herencia python
Python
0 vote241 views1 answer
Django.core.exceptions.ImproperlyConfigured: Application labels aren't unique, duplicates: auth
Python Django
1 vote201 views1 answer
Wheter
Python
0 vote272 views1 answer
Spacegoat meaning
Python
0 vote260 views1 answer
Access django server from another machine
Python Django
0 vote210 views1 answer
Pass arguments with apply
Python
0 vote205 views1 answer
Bar break matplotlib
Python
8 votes191 views3 answers
Python gzip file
Python
7 votes195 views3 answers
Python print exception type and message
Python
122 votes249 views3 answers
Iterate through keys in dictionary
Python