/Python/Numpy array divide each row by its sum

Numpy array divide each row by its sum

>>> e
array([[ 0.,  1.],
       [ 2.,  4.],
       [ 1.,  5.]])
# Method #1
>>> e/e.sum(axis=1)[:,None]
array([[ 0.        ,  1.        ],
       [ 0.33333333,  0.66666667],
       [ 0.16666667,  0.83333333]])

# Method #2
>>> (e.T/e.sum(axis=1)).T
array([[ 0.        ,  1.        ],
       [ 0.33333333,  0.66666667],
       [ 0.16666667,  0.83333333]])

# Method #3:
>>> e/e.sum(axis=1, keepdims=True)
array([[ 0.        ,  1.        ],
       [ 0.33333333,  0.66666667],
       [ 0.16666667,  0.83333333]])

Source: stackoverflow.com

Similar codes

0 vote149 views1 answer
How to parse timestamp in python
Python
0 vote137 views1 answer
To_datetime with non zero padded values python
Python
0 vote143 views1 answer
Python interpreter pip
Python
0 vote147 views1 answer
Fluffy ancake recipe
Python
2 votes140 views2 answers
For j in range(1,10,-1):
Python
-1 vote161 views1 answer
ModuleNotFoundError: No module named 'scipy'
Python
1 vote133 views1 answer
Convert all values in array into float
Python
0 vote162 views1 answer
How to do formatting in python with format function
Python
104 votes145 views5 answers
Split string in python
Python
2 votes145 views1 answer
Python check if string is date format
Python