/Python/Python unknow number of arguments, default argument,

Python unknow number of arguments, default argument,

def foo(a, b=3, *args, **kwargs):
  defaultKwargs = { 'c': 10, 'd': 12 }
  kwargs = { **defaultKwargs, **kwargs }
  print(a, b, args, kwargs)
  
  # Do something    

foo(1) # 1 3 () {'c': 10, 'd': 12}
foo(1, d=5) # 1 3 () {'c': 10, 'd': 5}
foo(1, 2, 4, d=5) # 1 2 (4,) {'c': 10, 'd': 5}

Source: stackoverflow.com

Similar codes

1 vote138 views1 answer
List.extend
Python
8 votes200 views2 answers
How to print all combinations of a string in python
Python
2 votes141 views3 answers
Nltk pip
Python
0 vote145 views1 answer
Cropping image google colab
Python
0 vote140 views1 answer
Python set workspace dir
Python
0 vote192 views1 answer
How to create api for get data in django rest framework
Python Django
0 vote147 views1 answer
Blender python get current filename
Python
0 vote139 views1 answer
Get video width and height cv2
Python
0 vote155 views2 answers
Python requests json backslash
Python
2 votes157 views2 answers
Python snippets
Python