/Python/Python unknow number of arguments, default argument,

Python unknow number of arguments, default argument,

def foo(a, b=3, *args, **kwargs):
  defaultKwargs = { 'c': 10, 'd': 12 }
  kwargs = { **defaultKwargs, **kwargs }
  print(a, b, args, kwargs)
  
  # Do something    

foo(1) # 1 3 () {'c': 10, 'd': 12}
foo(1, d=5) # 1 3 () {'c': 10, 'd': 5}
foo(1, 2, 4, d=5) # 1 2 (4,) {'c': 10, 'd': 5}

Source: stackoverflow.com

Similar codes

1 vote177 views2 answers
Subtract from dataframe column
Python
34 votes205 views5 answers
Convert pandas column type
Python
0 vote170 views1 answer
Accessing list inside dict python
Python
1 vote182 views2 answers
Code help
Python
1 vote224 views1 answer
R vs python
Python
0 vote178 views1 answer
Plt clor image histogram
Python
1 vote207 views1 answer
Open chrome console in selenium
Python
0 vote173 views1 answer
How to send jobs to queue dynamically
Python
10 votes169 views1 answer
How to get specific row in pandas
Python
25 votes411 views3 answers
Startapp django
Python Django