Drop if nan in column pandas

df = df[df['EPS'].notna()]

Pandas drop rows with nan in a particular column

In [30]: df.dropna(subset=[1])   #Drop only if NaN in specific column (as asked in the question)
Out[30]:
          0         1         2
1  2.677677 -1.466923 -0.750366
2       NaN  0.798002 -0.906038
3  0.672201  0.964789       NaN
5 -1.250970  0.030561 -2.678622
6       NaN  1.036043       NaN
7  0.049896 -0.308003  0.823295
9 -0.310130  0.078891       NaN

Source: stackoverflow.com

Similar codes

1 vote112 views2 answers
Python: calculate number of days from today date in a data frame
Python
0 vote96 views2 answers
Torch.cat
Python
0 vote162 views1 answer
Limit characters in django template
Python Django
0 vote53 views1 answer
All python versions
Python
1 vote99 views1 answer
How to run commands in repl.ot
Python
1 vote106 views1 answer
How to print time python 3
Python
3 votes103 views1 answer
Module 'datetime' has no attribute 'strptime'
Python
18 votes101 views4 answers
Python strip newline from string
Python
1 vote96 views1 answer
Jupyter notebook "TypeError: 'numpy.ndarray' object is not callable"
Python
9 votes98 views1 answer
How to convert a set to a list in python
Python