Catch error python

import traceback

dict = {'a':3,'b':5,'c':8}
try:
  print(dict[q])
 
except:
  traceback.print_exc()
  
# This will trace you back to the line where everything went wrong. 
# So in this case you will get back line 5

Catch error data with except python

import sys
try:
	S = 1/0 #Create Error
except: # catch *all* exceptions
    e = sys.exc_info()
    print(e) # (Exception Type, Exception Value, TraceBack)

############
#    OR    #
############
try:
	S = 1/0
except ZeroDivisionError as e:
    print(e) # ZeroDivisionError('division by zero')

Similar codes

94 votes109 views5 answers
How to rename columns using panda object
Python
0 vote111 views1 answer
Check if numpy array contains only duplicates
Python
2 votes127 views3 answers
How to sum digits of a number in python
Python
0 vote117 views1 answer
Qiskit setup
Python
1 vote75 views1 answer
How to uninstall python idle on ubuntu
Python
0 vote116 views1 answer
ApiError('d984ac0ae28d4afda0ddb26e348db535', UploadError('path', UploadWriteFailed(reason=WriteError('malformed_path', None), upload_session_id='AAAAAAAAACLukDh6ck8ZUw'))) python
Python
0 vote127 views1 answer
How to respond to a number in python
Python
0 vote113 views1 answer
How to check object res in blender 3.0
Python
0 vote112 views1 answer
Python webbrowser close tab
Python
-2 votes150 views1 answer
Jwt authentication python flask
Python Flask