Catch error python

import traceback

dict = {'a':3,'b':5,'c':8}
try:
  print(dict[q])
 
except:
  traceback.print_exc()
  
# This will trace you back to the line where everything went wrong. 
# So in this case you will get back line 5

Catch error data with except python

import sys
try:
	S = 1/0 #Create Error
except: # catch *all* exceptions
    e = sys.exc_info()
    print(e) # (Exception Type, Exception Value, TraceBack)

############
#    OR    #
############
try:
	S = 1/0
except ZeroDivisionError as e:
    print(e) # ZeroDivisionError('division by zero')

Similar codes

0 vote197 views1 answer
Df filter out rows that appear more than x times
Python
0 vote196 views1 answer
Pandas row printed horizontally
Python
0 vote230 views1 answer
If the value is not in dict return default
Python
19 votes200 views5 answers
Pandas where retuning NaN
Python
0 vote407 views1 answer
Tabpy Configuration file with custom settings
Python
0 vote283 views1 answer
Python Write code that asks users to enter the year they were born. Print out how many years old they will turn in 2019.
Python
0 vote190 views1 answer
Getting python class from string
Python
-1 vote193 views2 answers
Np.apply_along_axis third dimension python
Python
5 votes189 views3 answers
Debugging python
Python
0 vote196 views1 answer
Creation 2eme fenetre tkinter
Python