Python regex for a url

import re

url = '<p>Hello World</p><a href="http://example.com">More Examples</a><a href="http://example2.com">Even More Examples</a>'

urls = re.findall('https?://(?:[-\w.]|(?:%[\da-fA-F]{2}))+', url)

>>> print urls
['http://example.com', 'http://example2.com']

Source: stackoverflow.com

Similar codes

2 votes98 views1 answer
Python click buttons on websites
Python
0 vote96 views1 answer
Example 1: Reset Index & Drop Old Index pandas
Python
6 votes126 views3 answers
Login system in django
Python Django
2 votes107 views6 answers
Scikit learn
Python
6 votes92 views2 answers
How to press enter python keyboard
Python
2 votes96 views1 answer
How to replace a word in csv file using python
Python
0 vote92 views1 answer
Mechanize python XE #26
Python
0 vote108 views1 answer
Poisson disc python
Python
0 vote105 views1 answer
How to print smallest number in python
Python
2 votes99 views1 answer
Creating data frame in python with for loop
Python