Python regex for a url

import re

url = '<p>Hello World</p><a href="http://example.com">More Examples</a><a href="http://example2.com">Even More Examples</a>'

urls = re.findall('https?://(?:[-\w.]|(?:%[\da-fA-F]{2}))+', url)

>>> print urls
['http://example.com', 'http://example2.com']

Source: stackoverflow.com

Similar codes

31 votes189 views4 answers
Python random generator from list
Python
0 vote203 views1 answer
What does triple quotes mean in python
Python
2 votes218 views1 answer
Save df to txt
Python
1 vote205 views1 answer
Python requests force ipv4
Python
0 vote356 views1 answer
Bulk upload with dictionary or list in django moels
Python Django
15 votes285 views6 answers
Python sqlite3
Python
0 vote192 views1 answer
How to make an ai
Python
-1 vote193 views4 answers
Python creare decoratori
Python
2 votes196 views2 answers
Requests sessions
Python
25 votes180 views3 answers
Store all files name in a folder python
Python